Question

What volume of the solution contains 0.25 mol of MgCl2, with 0.995 M MgCl2?

Answer 1

0.251 L

Step-by-step explanation:

c (concentration) = n(moles)/v(volume in litres)

0.995 M = 0.25 mol / v

v = 0.25 mol / 0.995 M

v = 0.251 L