Answer:
the moment of inertia of this system of masses about the y-axis is 99 kgm²
Step-by-step explanation:
Given the data in the question; 
mass m₁ = 5.0 kg at point ( 3.0, 4.0 )
mass m₂ = 6.0 kg at point ( 3.0, -4.0 ) 
Now, Moment of inertia 
 of this system of masses about the y-axis will be;
 of this system of masses about the y-axis will be;
Moment of inertia 
 ₓ = mixi²
ₓ = mixi²
Moment of inertia 
 = m₁x₁² + m₂x₂²
 = m₁x₁² + m₂x₂²
we substitute
Moment of inertia 
 = [ 5.0 × ( 3 )² ] + [ 6.0 × ( 3 )² ]
 = [ 5.0 × ( 3 )² ] + [ 6.0 × ( 3 )² ]
Moment of inertia 
 = [ 5.0 × 9 ] + [ 6.0 × 9 ]
 = [ 5.0 × 9 ] + [ 6.0 × 9 ]
Moment of inertia 
 = 45 + 54
 = 45 + 54
Moment of inertia 
 = 99 kgm²
 = 99 kgm²
Therefore, the moment of inertia of this system of masses about the y-axis is 99 kgm²