Question

In the circuit below, lamps P and Q are identical. The reading on the ammeter is 3A. The cell shown is of

emf. 6V

Answer 1

6V is the correct because it may

Answer 2

a. I = V/R

I = 3V / 1 ohm

I = 3A

b. The voltmeter reading across lamp P would be 3V.

c. The resistance of lamp P is 1 ohm.

To calculate the current flowing through the circuit, we can use Ohm's law, which states that current (I) is equal to voltage (V) divided by resistance (R). In this case, the voltage across the circuit is 3V and the resistance is 1 ohm. Plugging these values into the formula I = V/R gives us I = 3V / 1 ohm, which simplifies to I = 3A. This means that the current flowing through the circuit is 3 amperes.

To find the voltmeter reading across lamp P, we can simply use the given voltage of 3V.

Finally, to determine the resistance of lamp P, we can use the formula R = V/I, where R is resistance, V is voltage, and I is current. Using the given values of V = 3V and I = 3A, we get R = 3V / 3A, which simplifies to R = 1 ohm. Therefore, the resistance of lamp P is 1 ohm.