Question

A bag contains 4 Red, 5 Black and 2

Green beads.
A bead is taken at random, its color is
noted and is replaced.
A second bead is taken.
Find the probability of taking two green
beads.

Answer 1

`P( 2 \ green ) = (4)/(121)`

Explanation:

`Probability \ of \ green \ i n \ the \ first \ try = (2C_1)/(11C_1) = (2)/(11)\\\\Probability \ of \green \ i n \ the \ Second \ try = (2C_1)/(11C_1) = (2)/(11)\\\\Probability \ of \ 2 \ green = (2)/(11) * (2)/(11 ) = (4)/(121)`