Question

I need help solving for x

Answer 1

`x=63.0^o`

Explanation:

Given

`RS = 35`

`RT = 77`

The attached triangle

Required

Solve for x

The relationship between x, RS and RT is:

`\cos(x) = (RS)/(RT)`

This gives:

`\cos(x) = (35)/(77)`

`\cos(x) = 0.4545`

Take arc cos of both sides:

`x = \cos^(-1)(0.4545)`

`x=63.0^o` --- approximated