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(6 - i)(6 + i) multiplying complex numbers​

(6 - i)(6 + i) multiplying complex numbers​
asked 89.8k views
5 votes
(6 - i)(6 + i) multiplying complex numbers​

asked
User Ankur Verma
by
8.3k points

1 Answer

4 votes

Answer:


(6 - i)(6 + i) \\ = (36 + 6i - 6i - {i}^(2) ) \\ = 36 - {i}^(2) \\ = 36 - ( - 1) \\ = 36 + 1 \\ = 37

answered
User Anshul Nigam
by
8.0k points
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