Question

Please help!

Suppose that a population parameter is 0.1 and many samples are taken from the population. If the size of each sample is 90, what is the standard error of the distribution of sample proportions? O A. 0.032 . B. 0.072 O C. 0.095 O D. 0.055 SUBMIT​

Answer 1

`\text{A. 0.032}`

Explanation:

Let
`\sigma_p` be the standard error of the distribution of sample proportions.

Formula:

`\sigma_p=\sqrt{(P(1-P))/(n)}`, where
`P` is the population parameter and
`n` is sample size.

What we're given:

• 
  `P` of 0.1
• 
  `n` of 90

Substituting given values, we get:

`\sigma_p=\sqrt{(0.1(1-0.1)/(90)},\\\sigma_p=\sqrt{(0.1\cdot 0.9)/(90)},\\\sigma_p=√(0.001)\approx\boxed{\text{A. 0.032}}`