Question

2Al + 6HCl → 2AlCl3 + 3H2

You want to make 10 moles of AlCl3. How many moles of HCl does that require?

Answer 1

Answer: If you want to make 10 moles of
`AlCl_(3)` then 30 moles of HCl are required in the given reaction.

Step-by-step explanation:

The given reaction equation is as follows.

`2Al + 6HCl \rightarrow 2AlCl_(3) + 3H_(2)`

Here, 6 moles of HCl reacts with 2 moles of
`AlCl_(3)`. This means that 1 mole of
`AlCl_(3)` is obtained as follows.

`(6)/(2) HCl\\= 3 HCl`

Hence, 3 moles of HCl will give 1 mole of
`AlCl_3`. So, moles of HCl required to react with 10 moles of
`AlCl_(3)` is as follows.

`1 mol AlCl_3 = 3 mol HCl\\10 mol AlCl_(3) = 3 * 10 mol HCl\\= 30 mol HCl`

Thus, we can conclude that if you want to make 10 moles of
`AlCl_(3)` then 30 moles of HCl are required in the given reaction.