Question

Solve the equation algebraically please help i don’t understand!!

Answer 1

(0,-1)

Explanation:

Hi there!

We are given the system:

-2x+8y=-8

2x-3y=3

there are 3 ways to solve systems of equations: graphing, substitution, and elimination

let's solve this system by elimination, which we will add the 2 equations together to clear one variable, solve for the other variable, and plug the value of that variable to solve for the variable that was cleared earlier.

add the two equations together (-2x and 2x clear out to equal 0 and we'll have only y left.)

-2x+8y=-8

+

2x - 3y= 3

_________

5y=-5

divide by 5 on both sides

y=-1

now substitute y as -1 into one of the equations to solve for x

for example, we can do the second equation

2x-3(-1)=3

multiply

2x+3=3

subtract 3 from both sides

2x=0

divide by 2

x=0

therefore the answer is x=0, y=-1. If you need it as a point, it's (0,-1)

Hope this helps! :)

Answer 2

Hi there!

`\large\boxed{(0, -1)}`

-2x + 8y = -8

2x - 3y = 3

We must eliminate a variable to solve. We can add the two equations to eliminate x because -2 + 2 = 0:

-2x + 8y = -8

2x - 3y = 3

-----------------

0x + 5y = -5

5y = -5

y = -1

Substitute this value of y into an equation to solve for x:

-2x + 8(-1) = -8

-2x -8 = -8

x = 0

Thus, the solution of this system is:

(0, -1)