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The area of a rectangle can be represented by x^2−8x+12 . If the width is x − 6, what would be the length?

The area of a rectangle can be represented by x^2−8x+12 . If the width is x − 6, what would be the length?
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The area of a rectangle can be represented by x^2−8x+12 . If the width is x − 6, what would be the length?

asked
User Rajnish Suryavanshi
by
8.1k points

2 Answers

4 votes
Short Answer: x+2 because W is the width
answered
User Edalat Feizi
by
7.7k points
1 vote
ANSWER: Let length be L = x+6 and width be W.
Given:
(x+6)W = x2 +8x +12
W = (x2 +8x +12)/(x+6)
W= (x+6)(x+2)/x+6)
W= x+2
answered
User Lynda
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8.4k points
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