Question

Anyone have the answer for this

Answer 1

`\huge\bold{Given:}`

Length of the base = 16 km.

Length of the hypotenuse = 34 km.
`\huge\bold{To\:find:}`

✎ The length of the missing leg ''
`a`".

`\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}`

The length of the missing leg "a" is
`\boxed{30\:km}`.

`\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}`

Using Pythagoras theorem, we have

`({perpendicular})^(2) + ({base})^(2) = ({hypotenuse})^(2) \\ ⇢ {a}^(2) + ({16 \: km})^(2) = ({34 \: km})^(2) \\ ⇢ {a}^(2) + 256 \: {km}^(2) = 1156 \: {km}^(2) \\ ⇢ {a}^(2) = 1156 \: {km}^(2) - 256 \: {km}^(2) \\ ⇢ {a}^(2) = 900 \: {km}^(2) \\ ⇢a \: = \sqrt{900 \: {km}^(2) } \\ ⇢a = \sqrt{30 * 30 \: {km}^(2) } \\ ⇢a = 30 \: km`

`\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:`

`\huge\bold{To\:verify :}`

`( {30 \: km})^(2) + ({16 \: km})^(2) =( {34 \: km})^(2) \\ ⇝900 \: {km}^(2) + 256 \: {km}^(2) = 1156 \: {km}^(2) \\⇝1156 \: {km}^(2) = 1156 \: {km}^(2) \\ ⇝L.H.S.=R. H. S`

Hence verified. ✔

`\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘`