Question

Without putting the first card back, you pick a second card at random. 4, 5, 6, 7 What is the probability of picking an odd number and then picking an even number? Write your answer as a fraction or whole number

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Answer 1

Answer: 1/3

Explanation:

the card is not being replaced, so it is a dependent event.

Event A: picking an odd number

There are 4 cards total, and 2 odd numbered cards.

P(A) = 2/4 = 1/2

Event B: picking an even number.

There are now three cards total, because the card from Event A was not replaced. There are two even numbered cards.

P(B) = 2/3

P(A+B) = P(A) x P(B)

P(A+B) = 1/2 x 2/3 = 2/6 = 1/3