Question

The system of equations kx-5y = 2, 6x+2y = 7 has no solution, then k =

(a) -10 (b) -5 (c) -6 (d) -15​

Answer 1

(d) -15

Explanation:

Given system of equations are:

`\begin{cases}kx-5y=2\\\\6x+2y=7\end{cases}`

Since, given system of equations have no solution.

`\therefore (k)/(6)=(-5)/(2) \\eq(2)/(7)`

`\implies (k)/(6)=(-5)/(2)`

`\implies k=(6(-5))/(2)`

`\implies k=(-30)/(2)`

`\implies k=-15`