Question

A 20 ohm and 60 ohm light bulb are put in series together which one would be brighter?

Answer 1

Answer:

The 60 Ohm bulb would be brighter than the 20 Ohm bulb.

Step-by-step explanation:

Hi there!

Ohm's Law: V=IRV=IR where V is voltage, I is current and R is resistance

Power equation: P=VRP=VR

The greater the power of a bulb, the brighter it is.

The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:

P=2RP=I

2

R

Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.

I hope this helps!

Answer 2

The 60 Ohm bulb would be brighter than the 20 Ohm bulb.

Step-by-step explanation:

Hi there!

Ohm's Law:
`V=IR` where V is voltage, I is current and R is resistance

Power equation:
`P=VR`

The greater the power of a bulb, the brighter it is.

The bulbs are connected in series, meaning the the current travelling through each will be the same. Plug Ohm's law into the power equation so we just have I and R:

`P=I^2R`

Because the current stays the same, the bulb with greater resistance will have greater power, hence being brighter. Therefore, the 60 Ohm bulb would be brighter than the 20 Ohm bulb.

I hope this helps!