Question

Water is added to 215 mL of a 2.1 M solution of CaCl2 to increase the volume of the solution to 350. mL. What is the new concentration?

Answer 1

1.29 M

Step-by-step explanation:

since it's a dilution, the new concentration must be less than 2.1 M

c1V1 = c2V2

c2 = c1V1/V2 = (2.1 M×215 mL)/350 mL = 1.29 M