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Twice once number added to another number is 18. If the second number is equal to 12 less than 4 times the first number, find the first two numbers. 2x+y= 12 ; y= __x - __ I rea…

Twice once number added to another number is 18. If the second number is equal to 12 less than 4 times the first number, find the first two numbers. 2x+y= 12 ; y= __x - __ I rea…
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Twice once number added to another number is 18. If the second number is equal to 12 less than 4 times the first number, find the first two numbers.

2x+y= 12 ; y= __x - __

I really need help with the second part...

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User Gordie
by
8.6k points

1 Answer

7 votes

Explanation:

2x+y= 12

= 12,18

= 36

so the value of y is 36

value of x is 48

answered
User Simon Thiel
by
8.6k points
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