Question

A mixture of oxygen( O2), dinitrogen monoxide (N2O), and argon (Ar) has a total pressure of 0.98 atm. What is the partial pressure of N2O, if the partial pressure of O2 is 0.48 atm and the partial pressure of Ar is 0.15 atm?

Answer 1

Answer: The partial pressure of
`N_(2)O` is 0.35 atm.

Step-by-step explanation:

Given: Total pressure = 0.98 atm

Partial pressure of
`O_(2)` = 0.48 atm

Partial pressure of Ar = 0.15 atm

Partial pressure of
`N_(2)O` = ?

Total pressure is the sum of partial pressure of each component present in a mixture of gases.

Hence, partial pressure of
`N_(2)O` is calculated as follows.

Total pressure =
`P_{N_(2)O} + P_{O_(2)} + P_(Ar)`

Substitute the values into above formula as follows.

`Total pressure = P_{N_(2)O} + P_{O_(2)} + P_(Ar)\\0.98 atm = P_{N_(2)O} + 0.48 atm + 0.15 atm\\P_{N_(2)O} = 0.35 atm`

Thus, we can conclude that the partial pressure of
`N_(2)O` is 0.35 atm.