Question

TanA+TanB=TanA+TanB÷1-TanA×TanB if A=30 andB=60​

Answer 1

`\tan (30 + 60) = unde f ined`

Explanation:

Given

`\tan (A + B) = (\tan A + \tan B)/(1 - \tan A * \tan B)` ---- right expression

`A = 30^o; B = 60^o`

Required

Solve

`\tan (A + B) = (\tan A + \tan B)/(1 - \tan A * \tan B)`

Substitute:
`A = 30^o; B = 60^o`

`\tan (30 + 60) = (\tan 30 + \tan 60)/(1 - \tan 30 * \tan 60)`

In radical forms, we have:

`\tan (30 + 60) = (\sqrt 3/3 + \sqrt 3)/(1 - \sqrt 3/3 * \sqrt 3)`

`\tan (30 + 60) = (\sqrt 3/3 + \sqrt 3)/(1 - 1)`

`\tan (30 + 60) = (\sqrt 3/3 + \sqrt 3)/(0)`

`\tan (30 + 60) = unde f ined`