Question

You have just landed your first job as a structural engineer and you have been asked to design a regional airport for small planes. Your manager informs you that the planes that will use this runaway must reach a speed before takeoff of at least 28.1 m/s, and can accelerate at 2 m/s2. What is the minimum length your runaway must have to facilitate a safe take off

Answer 1

Answer:
`197.40\ m`

Step-by-step explanation:

Given

final velocity at takeoff
`v=28.1\ m/s`

Acceleration of the plane can be
`a=2\ m/s^2`

Initial velocity is zero for the plane i.e.
`u=0`

Using the equation of motion

`\Rightarrow v^2-u^2=2as\quad [\text{s=displacement}]\\\text{Insert the values}\\\Rightarrow (28.1)^2-0=2* 2* s\\\\\Rightarrow s=(789.61)/(4)\\\\\Rightarrow s=197.40\ m`

Thu,s the minimum length must be
`197.40\ m`