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1 vote
A certain television is advertised as a 59-inch TV (the diagonal length). If the width of

the TV is 49 inches, how tall is the TV? Round to the nearest tenth of an inch.

1 Answer

4 votes

Answer:

32.9 inches

Explanation:

this can be solved using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base = 49

c = hypotenuse = diagonal = 59

l² + 49² = 59²

l² = 59² - 49²

3481 - 2401 = 1080

find the square root

32.9 in

answered
User Rodnower
by
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