Question

Find sin 0, sec 0, and tan 0, where is the angle shown in the figure.

Give exact values, not decimal approximations.

Answer 1

`Let \ base = x\\5^2 = x^2 + 4^2\\25-16 = x^2\\9 = x^2\\x = 3\\\\\\opposite = 4\\adjacent = 3\\hypotenuse = 5\\Sin \theta = (opposite)/(hypotenuse) = (4)/(5) \\\\Cos\theta = (adjacent)/(hypotenuse) =(3)/(5)\\\\Tan \theta = (opposite)/(adjacent) = (4)/(3)`