Question

Please help me with this question

Answer 1

`y = e^(x^2 - 3x)\\\\\\Let \ u = x^2 - 3x\\\\y = e^u\\\\(dy)/(du) = e^u\\\\(du)/(dx) = 2x - 3\\\\y' = (dy)/(dx) = (dy)/(du) *(du)/(dx) = e^u * (2x -3)\\\\Substitute \ u = x^2 -3\\\\y' = (2x -3)e^(x^2-3x)\\\\option A`