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A spring with a spring constant of 25.0N/m is stretched 4.50m. What is the force that the spring would apply?​

A spring with a spring constant of 25.0N/m is stretched 4.50m. What is the force that the spring would apply?​
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A spring with a spring constant of 25.0N/m is stretched 4.50m. What is the force that the spring would apply?​

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User Fiach Reid
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1 Answer

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Step-by-step explanation:


from \: hookes \: law : \\ force = k \bold{.}e \\ = 25.0 * 4.50 \\ = 112.5 \: N

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User CAdaker
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