asked 68.8k views
5 votes
A coach throws a football from a height of 4 feet with an initial velocity of 59 feet per second at an elevation angle of 45°. Which parametric equations represent the path of the football?

A. x(t) = 59sin(45°)t and y(t) = –16t^2 + 59cos(45°)t
B. x(t) = 59cos(45°)t and y(t) = –16t^2 + 59sin(45°)t
C. x(t) = 59cos(45°)t and y(t) = –16t^2 + 59sin(45°)t + 4
D. x(t) = 59sin(45°)t and y(t) = –16t^2 + 59sin(45°)t + 4

Answer is C. Add an answer so it won't be archived!

2 Answers

5 votes

Answer:

C

Explanation:

answered
User Uninvited Guest
by
8.3k points
4 votes
C.) x(t)=59cos(45)t and y(t)=-16^2 +59sin(45)t + 4
answered
User Nyarian
by
8.2k points
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