Question

Question 3 (1 point) A circle has its center of (0.0) and passes through the point (0.9). What is the standard equation of the circle​

Answer 1

x^2 + y^2 = 3^2

Explanation:

Start with (x - h)^2 + (y - k)^2 = r^2.

If the center is at (0, 0), we then have x^2 + y^2 = r^2.

If this circle passes through (0, 9), then 0^2 + 9^2 = r^2, and r must be 3.

Then the standard equation of this circle i

x^2 + y^2 = 3^2