asked 74.9k views
2 votes
A quadratic function f whose zeros are -3,-8

asked
User Santrack
by
7.9k points

1 Answer

5 votes

Answer:


x^2+11x+24=0

Explanation:

Given that,

The zeros of a quadratic function are -3 and -8

It means,

(x+3) = 0 and (x+8)=0

Now multiply them together,


(x+3)(x+8)=0\\\\x^2+8x+3x+24=0\\\\x^2+11x+24=0

Hence, the required equation is equal to
x^2+11x+24=0.

answered
User Tanchap
by
7.9k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.