Question

Select the two values of x that are roots of this equation.

+ 33-3=0
A. x.-345
-3-√21
2
c. x = -3+727
D.
-3- v3
2

Answer 1

A and B

`{x}^(2) + 3x - 3 = 0 \\ x = \frac{ - b± \sqrt{ {b}^(2) - 4ac} }{2a} \\ x = ( - 3± √(21) )/(2)`