Question

What is the binding energy of 1 mole of 23 Pu if the mass defect is 0.001896 kg/mol?

Answer 1

1.7 * 10^14 J

Step-by-step explanation:

Recall that binding energy = Δmc^2

Δm= mass defect

c = speed of light

Given that;

Δm = 0.001896 kg/mol/1 mol = 0.001896 kg

c=3 * 10^8 m/s

Binding energy = 0.001896 kg (3 * 10^8 m/s)^2

Binding energy = 1.7 * 10^14 J