asked 48.9k views
11 votes
a vertical pole cast a shadow of 20m long when the altitude of the sun is 60°what is the height of the pole?​

asked
User Gemfield
by
7.8k points

2 Answers

7 votes


\tt Tg~\alpha =(height~of~the~pole)/(shadow)\\\\height=Tg~60* 20=34.64~m

answered
User Anders Elton
by
7.8k points
5 votes

Answer:

20√3

Explanation:

20 x tan(60°)

=

20√3

answered
User Deadwards
by
8.6k points

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