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What are the roots (solutions) of the polynomial equation:x^3-2x^2=15x

asked
User Mseo
by
7.3k points

1 Answer

13 votes

Answer:

x = 0, 5, -3

Explanation:

You start by factoring
x^3-2x^2=15x which turns into
x(x+3)(x-5)=0 from here, you set factors equal to 0.

x=0, x would be 0

(x+3)=0, x would be -3

(x−5)=0, x woud be 5

answered
User Gadget
by
7.7k points

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