A spring is hung from the ceiling. When a coffee mug is attached to its end, it stretches 2.5 cm before reaching its new equilibrium length. The block is then pulled down slight…

Question

asked Sep 6, 2022 181k views

1 Answer

Heavy · Answer 1 · 2022-09-11T15:26:48+0000

Answer:

Step-by-step explanation:

In equilibrium , weight of mug is equal to restoring force .

mg = kx where m is mass of mug , k is spring constant and x is extension .

k / m = g / x = 9.8 ms⁻² / .025 m

= 392

frequency of oscillation n =
$(1)/(2\pi)\sqrt{(k)/(m) }$

$n=(1)/(2\pi)√(392 )$

= 4.46 per second.