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A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?

A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?
asked 154k views
2 votes
A person on a bike (m=90kg) is traveling 4m/s at the top of a 2m hill. What is his/her kinetic energy?

asked
User Poyraz Yilmaz
by
7.7k points

2 Answers

6 votes
Ke =(1/2 )mv^2
1/2(90*4)^2
720
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answered
User Arathi
by
8.4k points
3 votes

Answer:

Ek = 720J

Step-by-step explanation:

Ek = 0.5mv^2

Ek = 0.5(90)(4)^2

Ek = 720J

answered
User AudioDroid
by
8.0k points
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