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The width of a rectangle is 6 less than the length. A second rectangle with perimeter 54, is 3 wider and 2 shorter than the first. Find dimensions of each rectangle.​

The width of a rectangle is 6 less than the length. A second rectangle with perimeter 54, is 3 wider and 2 shorter than the first. Find dimensions of each rectangle.​
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The width of a rectangle is 6 less than the length. A second rectangle with perimeter 54, is 3 wider and 2 shorter than the first. Find dimensions of each rectangle.​

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User Genzotto
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1 Answer

8 votes

Check the picture below.


\stackrel{\textit{\large 1st rectangle}}{\stackrel{L}{16}*\stackrel{L-6}{10}}\qquad \qquad \stackrel{\textit{\large 2nd rectangle}}{\stackrel{L-2}{14}*\stackrel{(L-6)+3}{13}}

The width of a rectangle is 6 less than the length. A second rectangle with perimeter-example-1
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User Derdc
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