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Here is the other one.................
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Oct 13, 2022
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Here is the other one.................
Mathematics
high-school
Frank Thomas
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Answer:
2+2sec2∅tan²∅-sec⁴∅-tan⁴∅
2+2sec2∅tan²∅-sec⁴∅-tan⁴∅)
2-(sec⁴∅-2sec∅tan∅+tan⁴∅)
2-(sec²∅-tan²∅)²
2-(1)²
1 is a required answer.
[Note sec²x-tan²x=1]
Matt Hough
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Oct 19, 2022
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Matt Hough
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