Question

2sinx^2 =sin x+3
Solve for the solutions

Answer 1

x = 3/2 π (270°)

Explanation

2sin²x =sin x+3

2sin²x - sin x - 3 = 0

(sin x + 1) (2sin x - 3) = 0

-1 ≤ sin x ≤ 1

sin x = -1

x = 3/2 π (270°) or -π/2 + 2kπ (k = ..., -1, 0 , 1, ...)