9514 1404 393
Answer:
32 ft^2
Explanation:
The area can be figured several ways. Here are two of them.
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Add components
The figure can be divided into two smaller rectangles, (b) and (d) in the attached drawing. The area of each is the product of its dimensions.
Area b = (4 ft)(3 ft) = 12 ft^2
Area d = (10 ft)(2 ft) = 20 ft^2
Area of the figure is Area b + Area d = 12 ft^2 + 20 ft^2 = 32 ft^2.
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Subtract white space
The figure is bounded by an overall rectangle that is 10 ft wide and 5 ft high. The area of that rectangle is
Area a+b+c+d = (10 ft)(5 ft) = 50 ft^2
The area of whitespace 'a' is ...
Area a = (3 ft)(3 ft) = 9 ft^2
Area c has the same dimensions, so the same area. The area of the figure is the area of the bounding rectangle less the area of the two corner white spaces (a) and (c).
Area of the figure is ...
Area a+b+c+d -Area a -Area c = 50 ft^2 -9 ft^2 -9 ft^2 = 32 ft^2.