Question

What is the solution to the equation x^2-2x=-2

Answer 1

Explanation:

`{x}^(2) - 2x = - 2 \\ {x}^(2) - 2x + 2 = 0 \\ x = \frac{ - b± \sqrt{ {b}^(2) - 4ac} }{2a} \\ x = \frac{ - ( - 2)± \sqrt{ {( - 2)}^(2) - (4 * 1 * 2)} }{2 * 1} \\ x = (2± √( - 4) )/(2) \\ x = (2±2i)/(2) \\ x = (2 + 2i)/(2) \: or \: (2 - 2i)/(2) \\ x = 1 + i \: \: or \: \: 1 - i \\ x = 1±i`