A stone is dropped from a height of 7.70 m. How fast is it going when it reaches the ground? (Use energy to solve)

Question

asked Dec 21, 2022 67.9k views

2 Answers

Methyl · Answer 1 · 2022-12-26T02:32:38+0000

Answer:

v = 12.28 m/s

Step-by-step explanation:

Given that,

A stone is dropped from a height of 7.70 m.

We need to find the speed with which is it going when it reaches the ground. We can solve it using the conservation of energy as follows :

$(1)/(2)mv^2=mgh\\\\v=√(2gh) \\\\v=√(2* 9.8* 7.7) \\\\v=12.28\ m/s$

So, it is moving with a speed of 12.28 m/s when it reaches the ground.