Question

B) In the given figure, If AB = AC and < ABC = 65°, Find the value of

<ACB & <BAC.
A
65°
B
C​

Answer 1

<ACB =
`65^(o)` and <BAC =
`50^(o)`

Explanation:

The given triangle is an isosceles triangle. Thus its two sides are equal and base angles are equal.

So that;

<ACB = <ABC

<ACB =
`65^(o)` (property of an isosceles triangle)

Then,

<ABC + <ACB + <BAC =
`180^(o)`

`65^(o)` +
`65^(o)` + <BAC =
`180^(o)`

130 + <BAC =
`180^(o)`

<BAC =
`180^(o)` -
`130^(o)`

=
`50^(o)`

<BAC =
`50^(o)`

Thus, <ACB =
`65^(o)` and <BAC =
`50^(o)`.