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What is the pH when [H+] = 0.000032 M?

What is the pH when [H+] = 0.000032 M?
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What is the pH when [H+] = 0.000032 M?

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User Anton Harald
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1 Answer

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Step-by-step explanation:


pH = - log[H {}^( + ) ] \\ = - log(0.000032) \\ = 4.5

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User Pavel Dubinin
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