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Which of the following is the standard form of (x-7)2 + (y +1)2 = 16?

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User Nak
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1 Answer

3 votes

Answer:


(x - 7) {}^(2) + (y + 1) {}^(2) = 16 \\ this \: is \: an \: equation \: of \: circle \\ ( {x}^(2) - 14x + 49) + ( {y}^(2) + 2y + 1) = 16 \\ {x}^(2) + {y}^(2) - 14x + 2y + 50 = 16 \\ {x}^(2) {y}^(2) - 14x + 2y + 34 = 0

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User Peanut
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