Question

1. In the diagram below, the length of the legs AC and BC of right triangle ABC are 6 cm and 8 cm,

respectively. Altitude CD is drawn to the hypotenuse of AABC. What is the length of AD to the nearest tenth
of a centimeter?

Answer 1

Note that ABC is a 6 - 8 -10 right triangle with AB = 10

Also note that triangle ADC is similar to triangle ACB

Therefore

AD/ AC = AC / AB so

AD / 6 = 6/ 10 cross-multiply

10*AD = 6 * 6

810*AD = 36

AD = 36 / 10 = 3.6 = x

I hope this helps a little bit.