Examine the balanced equation for the reaction between lead(I) nitrate and sodium chloride.
 Pb(NO3)2 + 2NaCl → 2NaNO3 + PbCl2
 If 10.0 g of sodium chloride react with excess lead(II) nitrate, what mass of lead(II) chloride will be produced?
 0 20.8 g
 O 23.8 g
 O 47.68
 O 95.28