asked 181k views
3 votes
Examine the balanced equation for the reaction between lead(I) nitrate and sodium chloride.

Pb(NO3)2 + 2NaCl → 2NaNO3 + PbCl2
If 10.0 g of sodium chloride react with excess lead(II) nitrate, what mass of lead(II) chloride will be produced?
0 20.8 g
O 23.8 g
O 47.68
O 95.28

asked
User Chinjoo
by
8.4k points

1 Answer

5 votes
I think the answer is B
answered
User Gjqeriqi
by
7.9k points
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