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1 vote
Please help me I'm so bad at math and doing AFDA really doesn't help.. Its quadratic equations matching solution sets.

Please help me I'm so bad at math and doing AFDA really doesn't help.. Its quadratic-example-1

1 Answer

4 votes

Answer:


(a)\ x + 4 = \±\sqrt9 ----
x =\{-7,- 1\}


(b)\ x - 4 = \±\sqrt9 ----
x = \{1,7\}


(c)\ x + 3 = \±√(16) -----
x = \{-7,1\}


(d)\ x - 3 = \±√(16) ----
x = \{-1,7\}

Explanation:

Given

The attached equations

Required

Match each with the solution


(a)\ x + 4 = \±\sqrt9

Take the square root of 9


x + 4 = \±3

Solve for x


x =- 4 \±3

Split


x =\{- 4 -3,- 4 +3\}


x =\{-7,- 1\}


(b)\ x - 4 = \±\sqrt9

Take the square root of 9


x - 4 = \±3

Solve for x


x = 4 \±3

Split


x = \{4 -3,4+3\}


x = \{1,7\}


(c)\ x + 3 = \±√(16)

Take the square root of 16


x + 3 = \±4

Solve for x


x =- 3 \±4

Split


x = \{-3-4,-3+4\}


x = \{-7,1\}


(d)\ x - 3 = \±√(16)

Take the square root of 16


x - 3 = \±4

Solve for x


x =3 \±4

Split


x = \{3-4,3+4\}


x = \{-1,7\}

answered
User AntonAL
by
7.4k points
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