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What are the solutions to log6(x^2 + 8) = 1 +log6(x)? X=-2 and x=-4 X=-1 and x = 8 X= 1 and X=-8 X= 2 and x=4

What are the solutions to log6(x^2 + 8) = 1 +log6(x)? X=-2 and x=-4 X=-1 and x = 8 X= 1 and X=-8 X= 2 and x=4
asked 2.5k views
3 votes
What are the solutions to log6(x^2 + 8) = 1 +log6(x)?

X=-2 and x=-4
X=-1 and x = 8
X= 1 and X=-8
X= 2 and x=4

asked
User Skibulk
by
8.2k points

2 Answers

6 votes
Answer: x = 4, x = 2


x² + 8 = 6x
answered
User Mathyn
by
7.7k points
1 vote

Answer:

D. x=2 and x=4

Explanation:

Hope this helps!! Have a great day!! ❤

answered
User Nishit Maheta
by
8.2k points
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