Question

I have a 3 yellow m&m's, 5 blue m&m's, and 4 red m&m's. What is the probability if I choose a red and do not not put it back and then choose a yellow?

Answer 1

8.3% probability

Explanation:

(3) YELLOW ⇒
`(3)/(12)` ⇒ 25%

(5) BLUE ⇒
`(5)/(12)` ⇒ 41.6%

(4) RED ⇒
`(4)/(12)` ⇒ 33.3%

║(12) IN TOTAL

`(4)/(12)` ⋅
`(3)/(12)` =
`(1)/(12)`

`(1)/(12)` = 8.3%

PROBABILITY OF (1) RED, AND (1) YELLOW ⇒ 8.3% probability