Question

Simplify 2x^2-7x-4/x^2-5x+4 What are the excluded values

Answer 1

x = 1

Explanation:

Given

`(2x^2-7x-4)/(x^2-5x+4)` ← factor numerator and denominator

=
`((x-4)(2x+1))/((x-4)(x-1))` ← cancel (x - 4) on numerator/ denominator

=
`(2x+1)/(x-1)`

The denominator of the rational expression cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x - 1 = 0 ⇒ x = 1 ← excluded value

Answer 2

On edge it is D, 1 and 4

Explanation:

Why was it impossible to find this answer