Question

Jesse’s age is two times Adam’s age and Adam is three years older than Denise. If the sum of their ages is 33, how old is each person.

Answer 1

Jesse = 18yrs

Adam = 9yrs

Denise = 6yrs

Explanation:

Denise = x

Adam = x+3

Jesse = 2(x+3)

x+x+3+2x+6 = 33

4x+9 = 33

4x = 33-9

4x = 24

x = 6yrs

Substitute :

Denise = 6

Adam = 6+3 = 9

Jesse = 2(6+3) = 2(9) = 18