Question

Find the roots of the quadratic equation 3x^2+64=2x^2/2 .

Answer 1

: x = +/- 4√2 i.

:
3x^2 + 64 = 2x^2/2
3x^2 + 64 = x^2
2x^2 + 64 = 0
2x^2 = -64
x^2 = -32
x = +/- √-32
x = +/- √16* -2
x = +/- 4√2 i.